作者：　　来源：　日期：2007-4-17 11:59:22　点击：

        count[1] += i >>> 29;
        int l = 64 - k;
        int j;
        if(i >= l)
        {
            md5Memcpy(buffer, abyte0, k, 0, l);
            md5Transform(buffer);
            for(j = l; j + 63 < i; j += 64)
            {
                md5Memcpy(abyte1, abyte0, 0, j, 64);
                md5Transform(abyte1);
            }
            k = 0;
        } else
        {
            j = 0;
        }
        md5Memcpy(buffer, abyte0, k, j, i - j);
    }
    private void md5Final()
    {//最终处理，将得到的128位（16字节）MD5码存放在digest数组中
        byte abyte0[] = new byte[8];
        Encode(abyte0, count, 8);
        int i = (int)(count[0] >>> 3) & 0x3f;
        int j = i >= 56 ? 120 - i : 56 - i;
        md5Update(PADDING, j);
        md5Update(abyte0, 8);
        Encode(digest, state, 16);
    }
    private void md5Memcpy(byte abyte0[], byte abyte1[], int i, int j, int k)
    {
        for(int l = 0; l < k; l++)
            abyte0[i + l] = abyte1[j + l];
    }
    private void md5Transform(byte abyte0[])
    {
        long l = state[0];
        long l1 = state[1];
        long l2 = state[2];
        long l3 = state[3];
        long al[] = new long[16];
        Decode(al, abyte0, 64);
        l = FF(l, l1, l2, l3, al[0], 7L, 0xd76aa478L);
        l3 = FF(l3, l, l1, l2, al[1], 12L, 0xe8c7b756L);
        l2 = FF(l2, l3, l, l1, al[2], 17L, 0x242070dbL);